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2x^2-3x+1=0, how do I solve this
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2x^2-3x+1=0, how do I solve this

2x^2-3x+1=0, how do I solve this-example-1
User Imacbest
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2x^2-3x+1=0
(2x -1)(x-1) = 0
2x - 1 = 0; x = 1/2
x - 1 = 0;x = 1

answer
x = 1/2 and x = 1
User Leandrojmp
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