Question

The table below shows four systems of equations:

System 1 4x − 5y = 2, 3x − y = 8

System 2 4x − 5y = 2, 3x − 2y = 1

System 3 4x − 5y = 2, 3x − 8y = 4/

System 44x − 5y = 2, 10x − 9y = 4

Which pair of systems will have the same solution?

System 1 and system 3, because the second equation in system 3 is obtained by adding the first equation in system 1 to two times the second equation in system 1


System 1 and system 3, because the second equation in system 3 is obtained by adding the first equation in system 1 to three times the second equation in system 1


System 2 and system 4, because the second equation in system 4 is obtained by adding the first equation in system 2 to two times the second equation in system 2


System 2 and system 4, because the second equation in system 4 is obtained by adding the first equation in system 2 to three times the second equation in system 2

Answer 1

its the last one hope this helps

Answer 2

To determine which system of equations would have the same solution, we evaluate each system of equations.

System 1 4x − 5y = 2, 3x − y = 8
x = 38/11
y = 26/11

System 2 4x − 5y = 2, 3x − 2y = 1
x = 1/7
y = -2/7

System 3 4x − 5y = 2, 3x − 8y = 4
x = -4/17
y = -10/17

System 4 4x − 5y = 2, 10x − 9y = 4
x = 1/7
y = -2/7


Therefore, the correct answer is option 3. System 2 and system 4 are equal, because the second equation in system 4 is obtained by adding the first equation in system 2 to two times the second equation in system 2.

4x− 5y = 2 2( 3x − 2y = 1)
----------------------- 10x - 9y = 4