Question

The reactant concentration in a second-order reaction was 0.560 m after 115 s and 3.30×10−2 m after 735 s . what is the rate constant for this reaction?

Answer 1

Use the formula for second order reaction:


`(1)/(C) = (1)/(C_0) + kt`

C = concentration at time t
C0 = initial conc.
k = rate constant
t = time

1st equation :
`(1)/(0.56) = (1)/(C_0) + 115k`

2nd Equation:
`(1)/(0.033) = (1)/(C_0) + 735k`

Find
`(1)/(C_0)` from 1st equation and put it in 2nd equation:


`(1)/(0.033) = (1)/(0.56) - 115k + 735k`


`(1)/(0.033) - (1)/(0.56) = 620k`

k = 0.046