168k views
2 votes
Find two consecutive even integers whose some is 66

User Arturgspb
by
6.5k points

2 Answers

5 votes

Answer:

32 & 34

Explanation:

Let's solve your equation step-by-step.

x+x+2=66

Step 1: Simplify both sides of the equation.

x+x+2=66

(x+x)+(2)=66(Combine Like Terms)

2x+2=66

2x+2=66

Step 2: Subtract 2 from both sides.

2x+2−2=66−2

2x=64

Step 3: Divide both sides by 2.

2x/2=64/2

x=32

32 +2 = 34

User JoshJoe
by
7.2k points
1 vote
2 consecutive even integers....x and x + 2

x + x + 2 = 66
2x + 2 = 66
2x = 66 - 2
2x = 64
x = 64/2
x = 32

x + 2 = 32 + 2 = 34

ur 2 integers are : 32 and 34
User Mockinterface
by
6.7k points
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