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"an average human has a heart rate of 70 beats per minute. if someone's heart beats at that average rate over a 70-yr lifetime, how many times would it beat?"

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Answer : The number of beats (N) in the lifetime is
2.6* 10^9 beats.

Explanation :

First we have to determine the life time (T) of the person in the unit of minutes.

T = 70 year = (70 × 365 × 24 × 60) minutes

Conversions used :

1 year = 365 days

1 day = 24 hours

1 hour = 60 minutes

As we are given the rate (R) of the heart beat is, 70 beats/minutes.

R = 70 beats/minutes

Now we have to determine the number of beats (N) in the lifetime.

N = RT

N = (70 beats/minutes) × (70 × 70 × 365 × 24 × 60) beats

N =
2.6* 10^9 beats

Therefore, the number of beats (N) in the lifetime is
2.6* 10^9 beats.

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