Question

How many grams of NaCl are needed to form a 5.00 M solution with 450. ml?Na = 22.990 g/molCl = 35.453 g/mol

Answer 1

The number of moles of NaCl required to form 5M of 450 ml solution is,

`\begin{gathered} N=450ml*(5)/(1000)Mml^(-1) \\ N=2.25M\text{ } \end{gathered}`

The mass of the NaCl is,

`M=m_(Na)+m_(Cl)`

Substituting the known values,

`\begin{gathered} M=22.99+35.453 \\ M=58.443\text{ gm} \end{gathered}`

Thus, the amount of NaCl required in gm to make the given solution is,

`\begin{gathered} M^(\prime)=M* N \\ M^(\prime)=58.443*2.25 \\ M^(\prime)=131.5\text{ gm} \end{gathered}`

Hence, the amount of NaCl equired for the given solution is 131.5 gm