x³ +2x² +x +2
1) Since we have -i and -2 we can rewrite them as factors as complex numbers
into a +bi form. So,
Let's pick the conjugate (a -bi) of those numbers and write as factors. We need 3 factors for a 3rd-degree polynomial.
(x+2)(x+i)(x-i) Distribute the factors
(x+2)(x²-i²) Remember and plug i²=-1
(x+2)(x²+1)
x³ +x+2x²+2
x³ +2x² +x +2