Question

James and Bethany Morrison are celebrating their 10th anniversary by having a reception at a local reception hall. Theyhave budgeted $4,500 for their reception. If the reception hall charges a $60 cleanup fee plus $38 per person, find thegreatest number of people that they may invite and still stay within their budget.?

Answer 1

Given that:

- James and Bethany have budgeted $4,500 for their reception.

- The reception hall charges a $60 cleanup fee.

- The reception hall also charges $38 per person.

Let be "x" the number of people that they may invite and still stay within their budget.

You know that the total amount of money should be less than or equal to $4,500. Then, knowing all the amount of money the reception hall charges, you can set up the following inequality to represent the situation:

`60+38x\leq4500`

Now you have to solve for "x":

`38x\leq4500-60`
`38x\leq4440`
`x\leq(4440)/(38)`
`x\leq116.842`

Notice that you got a decimal number. If you set up that:

`x\approx116`

You obtain that:

`60+38(116)\leq4500`
`4468\leq4500\text{ \lparen True\rparen}`

Hence, the answer is:

`116\text{ }people`