Question

An urn holds 5 white and 3 black marbles. if 2 marbles are to be drawn at random without replacement and x denotes the number of white marbles, find the probability distribution for x

Answer 1

To find the probability distribution for x, consider the possible values of x and calculate the probability of each value. When 2 marbles are drawn without replacement, there are two possible outcomes. The probability distribution for x is P(x = 0) = 3/28, P(x = 1) = 15/56, and P(x = 2) = 5/14.

Step-by-step explanation:

To find the probability distribution for x, we need to consider the possible values of x and calculate the probability of each value.

Since there are 5 white marbles and 3 black marbles in the urn, the total number of marbles is 8.

When 2 marbles are drawn without replacement, there are two possible outcomes: (1) both marbles are white and (2) one marble is white and one marble is black.

Let's calculate the probabilities:

P(x = 0) = P(both marbles are black) = (3/8) * (2/7) = 6/56 = 3/28

P(x = 1) = P(one marble is white and one marble is black) = (5/8) * (3/7) = 15/56

P(x = 2) = P(both marbles are white) = (5/8) * (4/7) = 20/56 = 5/14

Therefore, the probability distribution for x is:

P(x = 0) = 3/28

P(x = 1) = 15/56

P(x = 2) = 5/14

Answer 2

i =
`p(0) = \frac {3} {8} x \frac {2} {7} = \frac {3} {28} ; p (1) = \frac {3} {8} x \frac {5} {7} + \frac {5} {8} x \frac {3} {7} = \frac {15} {28}; p (2) = \frac {5} {8} x \frac {4} {7} = \frac {5} {14}`

(a) i. The probability mass function of X is 5 / 14

Hypergeometric Distribution is the probability distribution of a hypergeometric random variable.

The hypergeometric distribution is used to calculate the statistical importance of having drawn a specific k successes (out of n total draws) from the aforementioned population in the hypergeometric test uses.

ii. Please see attached image for the answer.