Question

A projectile is launched with an initial velocity of 25m/s at 35 degrees above the horizontal. assuming that the projectile returns to the same height, what is the final velocity of this projectile

Answer 1

The final velocity of a projectile launched at an angle above the horizontal and returning to the same height is equal to its initial velocity in the opposite direction.

Step-by-step explanation:

When a projectile is launched at an angle above the horizontal and returns to the same height, its final velocity will have the same magnitude as its initial velocity but in the opposite direction. This is because the horizontal component of velocity remains constant while the vertical component changes due to the force of gravity. In this case, the initial velocity is 25 m/s and the angle is 35 degrees above the horizontal, so the final velocity will also be 25 m/s but in the opposite direction.

Answer 2

Speed is the same as the initial: 25m/s.

*if* you need vectors though:

final velocity = (25*cos(35), -25*sin(35) ) m/s