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What volume of 1.25M HCl would be required to prepare 180 mL of a 0.500M HCl solution? A. 2.2 x 103 mL B. 450 mL C. 72 mL D. 0.014 mL

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To solve this we use the dilution equation used in chemistry,

M1 V1 = M2 V2

where M1 is the concentration of the stock solution, V1 is the volume of the stock solution, M2 is the concentration of the new solution and V2 is its volume.

M1 V1 = M2 V2

1.25 M x V1 = 0.500 M x 180 mL

V1 =72 mL of the concentrated solution

Therefore, the correct answer would be option C.

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