Question

If f(x) = sqrt x-3, which inequality can be used to find the domain of f(x)?

sqrt x-3 >/= 0
x - 3 >/= 0
sqrt x - 3 = 0
x - 3 = 0

Answer 1

Answer: B: x-3 >_ 0

Explanation:

Took test

Answer 2

Assuming all of "x-3" is under the square root, then the answer is
`x -3 \ge 0` which can be written as x - 3 >= 0 which looks like it points to choice B as the answer

The goal is to figure out which x values will make "x-3" nonnegative (not negative). Taking the square root of a negative number leads to a non-real result. So it's a common thing to make the radicand (stuff under the square root) positive or 0.