Find the possible value or values of n in the quadratic equation 2n^2-7n+6=0

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asked Jun 28, 2018 44.9k views

1 Answer

Dagrada · Answer 1 · 2018-07-03T17:07:50+0000

Using the quadratic formula:
n = [-b +- sq root (b^2 -4*a*c)] / 2a
n = [--7 +- sq root (49 -4*2*6)] / 4
n = [--7 +- sq root (49 -48)] / 4
n = [--7 +- sq root (1)] / 4
n1 = (7 + 1) / 4
n1 = 2

n2 = (7 -1) / 4
n2 = 1.5

Find the possible value or values of n in the quadratic equation 2n^2-7n+6=0

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