Question

Select the factors of 6ab + 3ay − 2bx − xy.

A. (3a − x)(2b + y)
B. (3a − y)(2b + x)
C. (2a − x)(3b + y)
D. (2a − y)(3b + x)

I need the answer I don't get it ...and this is a really long test ..but so far I only need help on this one . thanks to whoever helps me and give correct answer

Answer 1

answer
A. (3a − x)(2b + y)

cause

(3a − x)(2b + y) = 6ab + 3ay -2bx -xy (expand by using distributive property)

Answer 2

The factors of given expression is (3a-x)(2b+y)

A is correct

Explanation:

Given:
`6ab+3ay-2bx-xy`

We need to factor the given expression.

First we make two group

`\Rightarrow (6ab+3ay)+(-2bx-xy)`

Factor each group

`\Rightarrow 3a(2b+y)-x(2b+y)`

`\Rightarrow (3a-x)(2b+y)`

So, we get two factor (3a-x) and (2b+y)

Hence, The factors of given expression is (3a-x)(2b+y)