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Let (-7, -4) be a point on the terminal side of theta. Find the exact values of Sin, CSC and COT

User Exagon
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The above is saying sin = y divided by r = -4 divided by the square root of 65.
User Angus Ireland
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First you need to get the radius of the circle. We do that by using the (x,y) point. So we have (-7, -4).

To get the radius, we us the following formula.

r = √(-7)² + (-4)²

This reads:
radius = square root of -7 to the power of 2 plus -4 to the power of 2.

I am new here and I am not sure if they support latex. Other wise I would of used latex.

Ok so r (radius) = r = √(-7)² + (-4)² = √65

r = √65

Now we have our radius we can find the values for sin csc and cot

sin = y / r
csc = r / y
cot = x / y

I will do the first one for you which is sin.

sin = y / r = -4 / √65

The above is saying sin = y divided by r = -4 divided by the square root of 65.

If you need help with the others let me know.



User Paulo Malvar
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