I have a homework, i need an answer without explanation

Tiep Phan asked Sep 27, 2023

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Tiep Phan asked Sep 27, 2023

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14 votes

Solution:

Given:

$\begin{gathered} (x+y)^2=1 \\ x^2+y^2=1 \\ x+y\leq0 \end{gathered}$

The graph of the functions is given below;

From the graph, the points that satisfy the conditions are;

$(0,-1)\text{ and }(-1,0)$

Therefore, the final answer is Two.

OPTION B.

Bjorsig answered Oct 2, 2023

3.0k points

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