Question

If 3 consecutive integers sum to 63, the largest of the 3 = ?

Answer 1

x+(x+1)+(x+2)=63
3x+3=63
3x=60
x=20
Consecutive integers are: 20, 21, 22
Answer: 22

Answer 2

This problem states that the sum of 3 consecutive integers is 63 and it asks us to find the largest integer.

Three consecutive integers can be represented as followed.

X → first integer

X + 1 → second integer

X + 2 → third integer

Since the sum of our three consecutive integers is 24, we can write an equation.

X + X + 1 + X + 2 = 63

We can simplify our equation on the left and it will read...

3x + 3 = 63

-3 -3

3x = 60

÷3 ÷3 ← divide both sides by 3

X = 20

Largest integer = X + 2

20 + 2 = 22

Largest integer = 22