Question

Please help on b (left of c) and c !!!

rewrite each of the following expressions so that your answer has no negative or fractional exponents

Answer 1

alrighty


remember

`(ab)^c=(a^c)(b^c)`
and

`x^(m)/(n)=\sqrt[n]{x^m}`
and

`image` for all real numbers x
and

`x^(-m)=(1)/(x^m)`


b.

`(x^5y^4)^(1)/(2)=((x^5)^(1)/(2))((y^4)^(1)/(2))`=

`(x^(5)/(2))(y^(4)/(2))=(√(x^5))(√(y^4))=x^2y^2√(x)`

c.
x^0=1
so
that (x^-3y)^0=1
because exponents first in pemdas
so we are left with
x^2y^-1

`x^2y^(-1)=(x^2)(y^(-1))=(x^2)((1)/(y^1))=(x^2)/(y)`

Answer 2

`(x^5y^4)^{ (1)/(2) }= √(x^5y^4) =x^2y^2 √(x) \\ \\ \\ (x^2y^(-1))(x^(-3)y)^0= (x^2y^(-1))*1= (x^2)/(y)`