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What is the slope of a line that is perpendicular to the line whose equation is 0.5x−5y=9 0.5 x − 5 y = 9

User Gemmi
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1 Answer

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i) one of the forms that we can write the equation of a line is

y=mx+k

where m is the slope of the line.

ii)

given lines y=mx+k and y=nx+t, which are perpendicular to each other.

Then, m*n=-1


Now consider the line 0.5x−5y=9:

0.5x−5y=9

take -5y to the right side and 9 to the left side

0.5x-9=5y

switch sides

5y=0.5x-9

divide by 5

y=0.1x-9/5

so the slope of the line is m=0.1

let the slope of the line perpendicular to
0.5x−5y=9 be n, then

0.1*n=-1

n=-1/(0.1)=-10


Answer: -10
User Patrick Pitre
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