Question

The decomposition of dinitrogen pentoxide is described by the chemical equation 2 n2o5(g) → 4 no2(g) + o2(g) if the rate of disappearance of n2o5 is equal to 1.80 mol/min at a particular moment, what is the rate of appearance of no2 at that moment?

Answer 1

The rate of appearance of NO2 when the rate of disappearance of N2O5 is 1.80 mol/min is 3.60 mol/min based on the stoichiometry of the reaction.

Step-by-step explanation:

The decomposition of dinitrogen pentoxide (N2O5) is described by the chemical equation 2 N2O5(g) → 4 NO2(g) + O2(g). The rate of disappearance of N2O5 is given as 1.80 mol/min. According to the stoichiometry of the reaction, 4 moles of NO2 are produced for every 2 moles of N2O5 that decompose. Therefore, the rate of appearance of NO2 at that moment would be twice the rate of the disappearance of N2O5, which is 1.80 mol/min * 2 = 3.60 mol/min.