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Differentiate
1/√x^2-1

User Pztrick
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1 Answer

4 votes
the function is
f(x)= \frac{1}{ \sqrt{ x^(2) -1}}

write f again as
f(x)= (x^(2) -1)^{- (1)/(2) }

(the power -1 takes the expression to the denominator, and the power 1/2 is square root)

writing rational expressions as power expressions, generally makes differentiation more practical.

In
f(x)= (x^(2) -1)^{- (1)/(2) } we notice 2 functions:

the outer function
u^{ -(1)/(2) }, where
u=x^(2) -1, and the inner, u itself , which is a function of x.

So we differentiate by using the chain rule:


f'(x)= -(1)/(2)u^{- (1)/(2)-1 }*u'= -(1)/(2)u^{- (3)/(2) }*(2x)=- \frac{x}{ \sqrt{ u^(3) } } =- \frac{x}{ \sqrt{ (x^(2) -1)^(3) } }


Answer:
- \frac{x}{ \sqrt{ (x^(2) -1)^(3) } }
User SimenB
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