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Please Help! I have 2 questions left. Suppose that there are two types of tickets to a show: advance and same-day. Advance tickets cost $20 and same-day tickets cost $40 . For one performance, there were
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Please Help! I have 2 questions left.

Suppose that there are two types of tickets to a show: advance and same-day. Advance tickets cost $20 and same-day tickets cost $40 . For one performance, there were 60 tickets sold in all, and the total amount paid for them was $1600 . How many tickets of each type were sold?

User Rezoner
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1 Answer

6 votes
You can make the system of equations:


20x+40y=1600

x+y-60

From here, you can solve and you will get : x=40 and y=20 so, 40 advance tickets were sold and 20 same-day tickets were sold.





User Kimiko
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