Question

URGENT!!!

Kay was walking along the bridge above the river. She accidentally lost her grip on her camera when she was trying to get it out to photograph massive bird nests in the trees. The height of the camera above the water can be modeled by the equation

y = -16t^2 + 400, where t represents the seconds after the camera is dropped. How long will it take (in seconds) before Kay sees the splash from the camera hitting the water.

Answer 1

5 seconds

Explanation:

Kay was walking along the bridge above the river. She accidentally lost her grip on her camera when she was trying to get it out to photograph massive bird nests in the trees. The height of the camera above the water can be modeled by the equation

y = -16t^2 + 400, where t represents the seconds after the camera is dropped.

When splash from the hits the water then the height becomes 0

height is y so we replace y with 0 and solve for t

0 = -16t^2 + 400

Subtract 400 on both sides

-400 = -16t^2

Divide by 16 on both sides

25= t^2

take square root on both sides

t= 5

It takes 5 seconds

Answer 2

The given equation in this case is:

y = -16 t^2 + 400

We can see that the slope of the equation is negative (-16) which means that the position of Kay is on the positive y-axis , while the bottom of the river is in the origin. This is supported by taking t = 0, the initial y becomes y = 400. Therefore the position of Kay now is at (0, 400).

So to find for the time when the camera hits the water, then y must be zero (t, 0) so we have to find for t in this case.

When y = 0

0 = -16 t^2 + 400

16 t^2 = 400

t^2 = 25

t = 5 s

Therefore it takes 5 seconds for the camera to hit the water and for Kay to see a splash.