Question

For which of the following is x=-5 a solution? Select all that apply. A) x+10=-5 B) -x^2+50=25 C) l2xl =10 D) x<0 E) 2x<10

Answer 1

Explanation:

Answer 2

Let's check each of the cases to determine the solution of the problem

case A) we have

`x+10=-5`

Substitute the value of
`x=-5` in the equation

`(-5)+10=-5`

`5=-5` ------> the equation is not true

therefore

The value of
`x=-5` is not a solution of the equation

case B) we have

`-x^(2) +50=25`

Substitute the value of
`x=-5` in the equation

`-(-5)^(2) +50=25`

`-(25) +50=25`

`25=25` ------> the equation is true

therefore

The value of
`x=-5` is a solution of the equation
`-x^(2) +50=25`

case C) we have

`\left|2x\right|=10`

Substitute the value of
`x=-5` in the equation

`\left|2(-5)\right|=10`

`\left|-10\right|=10`

`10=10` -----> the equation is true

therefore

The value of
`x=-5` is a solution of the equation
`\left|2x\right|=10`

case D) we have

`x < 0`

Substitute the value of
`x=-5` in the inequality

`-5 < 0` --------> the inequality is true

therefore

The value of
`x=-5` is a solution of the inequality
`x < 0`

case E) we have

`2x <10`

Substitute the value of
`x=-5` in the inequality

`2*(-5) < 10`

`-10 < 10` --------> the inequality is true

therefore

The value of
`x=-5` is a solution of the inequality
`2x <10`

the answer is

`-x^(2) +50=25`

`\left|2x\right|=10`

`x < 0`

`2x <10`