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ΔABC has three sides with these lengths: AB = 9, BC = 40, and CA = 41. What is the value of cos C?

ΔABC has three sides with these lengths: AB = 9, BC = 40, and CA = 41. What is the value of cos C?
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2 votes
ΔABC has three sides with these lengths: AB = 9, BC = 40, and CA = 41. What is the value of cos C?

User Michael Nguyen
by
8.3k points

2 Answers

4 votes

Answer:

The correct answer is

C 40/41

Explanation:

User Runeh
by
8.0k points
7 votes
41*41 = 1681
40*40 = 1600
9* 9 = 81
so a^2 = b^2 + c^2
1681 = 1600 + 81
1681 = 1681 ...it's right triangle

CA = 41 = Hypo.
cosC = Adj / Hypo
cosC = BC / CA = 40/41

answer
cosC = 40/41
User Nick Forge
by
7.6k points
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