Register
ΔABC has three sides with these lengths: AB = 9, BC = 40, and CA = 41. What is the value of cos C?
113k views
2 votes
ΔABC has three sides with these lengths: AB = 9, BC = 40, and CA = 41. What is the value of cos C?

User Michael Nguyen
by
8.3k points

2 Answers

4 votes

Answer:

The correct answer is

C 40/41

Explanation:

User Runeh
by
8.0k points
7 votes
41*41 = 1681
40*40 = 1600
9* 9 = 81
so a^2 = b^2 + c^2
1681 = 1600 + 81
1681 = 1681 ...it's right triangle

CA = 41 = Hypo.
cosC = Adj / Hypo
cosC = BC / CA = 40/41

answer
cosC = 40/41
User Nick Forge
by
7.6k points
← Prev Question Next Question →

No related questions found

Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.5m questions

12.2m answers

Other Questions

What is .725 as a fraction
How do you estimate of 4 5/8 X 1/3
A bathtub is being filled with water. After 3 minutes 4/5 of the tub is full. Assuming the rate is constant, how much longer will it take to fill the tub?
i have a field 60m long and 110 wide going to be paved i ordered 660000000cm cubed of cement  how thick must the cement be to cover field
Write words to match the expression. 24- ( 6+3)
Link Copied!