Final answer:
When 975 kJ of heat are liberated in the process of converting galena (PbS) to lead oxide (PbO), a mass of 563.8 grams of galena is converted based on the reaction stoichiometry.
Step-by-step explanation:
The student is asking about the extraction process of lead from galena (PbS) where heat is liberated. To calculate the mass of galena converted to lead oxide (PbO) when 975 kJ of heat are released, we will use stoichiometry based on the given thermochemical equation:
2 PbS (s) + 3 O2 (g) → 2 PbO (s) + 2 SO2 (g) ΔH = −827.4 kJ
This shows that for every 827.4 kJ of heat released, 2 moles of PbS are converted to PbO. Using the molar mass of PbS (239.26 g/mol), the conversion from kJ to mass can be performed as follows:
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- First, find out how many kJ corresponds to one mole of PbS: 827.4 kJ for 2 moles, so 827.4 kJ / 2 = 413.7 kJ/mole.
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- Next, calculate the number of moles of PbS corresponding to 975 kJ: 975 kJ / 413.7 kJ/mole = 2.356 moles.
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- Finally, convert moles of PbS to mass: 2.356 moles * 239.26 g/mole = 563.8 grams.
Therefore, 563.8 grams of galena are converted to lead oxide with the liberation of 975 kJ of heat.