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By how much does a^3 - 2a exceed a^2 + a - 6?

1 Answer

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Answer

a³ - a² - 3a + 6


Step-by-step explanation

The equation requires you to subtract the two expressions.

(a³ - 2a) - (a² + a - 6)

In such an expression we subtract the like term only.

(a³ - 2a) - (a² + a - 6) = a³ - 2a - a² - a + 6

= a³ - a² -2a - a + 6

= a³ - a² - 3a + 6

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