Question

What are the discontinuities of the function f(x) = the quantity of x squared plus 5 x plus 6, all over 2 x plus 16. ?

Answer 1

Explanation:

Since f(x) = (x^2 + 5x + 6) / (2x + 16)

For discontinuities, they can be found at where the slope does NOT exist

Take the derivative of f(x):

f'(x) = (x^2 + 16x + 34) / 2(x+8)^2

Apparently, when x= -8, f'(x) is NOT defined

Therefore, the discontinuity is uniquely located at x = -8

Answer 2

Since f(x) = (x^2 + 5x + 6) / (2x + 16)

For discontinuities, they can be found at where the slope does NOT exist

Take the derivative of f(x):

f'(x) = (x^2 + 16x + 34) / 2(x+8)^2

Apparently, when x= -8, f'(x) is NOT defined

Therefore, the discontinuity is uniquely located at x = -8