198,656 views
40 votes
40 votes
Determine the value of pif f (x) is continuous at x = 3. Refer to the picture given.

User Geerten
by
2.4k points

1 Answer

13 votes
13 votes

Given:-


f(x)=\begin{cases}(x^2-12x+27)/(x-3) \\ 6px\end{cases}

To find the value of x=3.

From the question it is clear that the value of 3 lies within,


(x^2-12x+27)/(x-3)

Now we substituting the value of x=3. we get,


\begin{gathered} f(x)=(x^2-12x+27)/(x-3)_{} \\ f(3)=(3^2-12*3+27)/(3-3) \\ f(3)=(9-36+27)/(0) \\ f(3)=(0)/(0) \end{gathered}

So the value of f(3)=0

User Boken
by
3.0k points