Question

What is the vertex of y=3x^2+6x+5

Answer 1

`\bf \textit{ vertex of a vertical parabola, using coefficients}\\\\ \begin{array}{llcclll} y = &{{ 3}}x^2&{{ +6}}x&{{ +5}}\\ &\uparrow &\uparrow &\uparrow \\ &a&b&c \end{array}\qquad \left(-\cfrac{{{ b}}}{2{{ a}}}\quad ,\quad {{ c}}-\cfrac{{{ b}}^2}{4{{ a}}}\right)`