Question

.

The value of x is:


12.
6.

`12\sqrt{2`
None of the choices are correct.

Answer 1

`\bf \textit{using the pythagorean theorem}\\\\ c^2=a^2+b^2\implies c=√(a^2+b^2)\qquad \begin{cases} c=hypotenuse=x\\ a=adjacent=12\\ b=opposite=12\\ \end{cases} \\\\\\ x=√(12^2+12^2)\implies x=√(288)\implies x=√(12^2\cdot 2) \\\\\\ x=12√(2)`