2 Answers

Steffen Winkler · Answer 1 · 2019-01-01T06:00:41+0000

The solutions to the equation are
(2 +/- √(15)))/(11) .

You can find the answer to any quadratic by using the quadratic formula. The formula is below.

$\frac{-b +/- \sqrt{b^(2)-4ac}}{2a}$

Then find a (the number attached to x^2), b (the number attached to x) and c (the constant). This will allow you to plug in and solve.

$\frac{4 +/- \sqrt{-4^(2)-4(11)(-1)}}{2(11)}$

(4 +/- √(16 + 44))/(22)

(4 +/- √(60)))/(22)

(2 +/- √(15)))/(11)

Please log in or register to add a comment.