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A ball is thrown into the air with an upward velocity of 36 ft/s. Its height h in feet after t seconds is given by the function h=-16t^2+36t+5. In how many seconds does the ball reach its maximum height? Round to the nearest hundredth if necessary. What is the ball’s maximum height

1)1.13 s; 27.5 ft

2)2.25 s; 5 ft

3)1.13 s; 25.25 ft

4)1.13 s; 65.75 ft

User Lukewitmer
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Answer: 1.13s;25.25ft you welcome

Explanation:

User Sandsten
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The time can be found with -b/2a, and the time is -36/2*-16 = 1.13 seconds. Plugging back into the equation we get h = 25.25 feet.
User Rob Farley
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