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5 votes
Factor the expression.

4r^2 – 64

1)(4r + 5)(r – 16)
2)4(r – 4)(r – 4)
3)(4r – 5)(r + 16)
4)4(r + 4)(r – 4)

User Jay Bharat
by
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2 Answers

2 votes
4r^2-64
4(r^2-16)
4(r+4)(r-4)
First factor out the gcf. Because (r^2-16) has perfect squares, you can factor it out one more time.
Final answer: D
User Omar Freewan
by
8.2k points
3 votes
Hey!

First, let's write the problem,

4r^2-64
Factor out the common term, which is 4,

=4\left(r^2-16\right)
Then, let's factor this part:
r^2-16
We are going to factor it using the difference of squares rule.

=\left(r+4\right)\left(r-4\right)
Our final factored answer would be,

=4\left(r+4\right)\left(r-4\right)

Thanks!
-TetraFish
User Stig Hausberg
by
8.3k points

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