Question

Four forces are being applied to move an object to the left. Force 1 is pushing to the right at 200 N. Force 2 is pushing to the left at 500 N. Force 3 is pushing to the right at 100 N. Force 4 is pushing to the left at 50 N. What's the net force acting on this object?

Answer 1

200 + 100 = 300

500 + 50 = 550

550 - 300 = 250

Answer : 250 N

Answer 2

Net force is 250 N and it act in right direction.

Step-by-step explanation:

It is given that, four forces are being applied to move an object to the left. Let the force acting on the left is F. Force 1 is pushing to the right at 200 N. Force 2 is pushing to the left at 500 N. Force 3 is pushing to the right at 100 N. Force 4 is pushing to the left at 50 N.

So, net force acting on left is : F + 500 N +50 N

Net force acting right is : 200 N + 100 N

i.e.
`F+500+50=200+100`

F = -250 N

So, the net force acting on the object is 250 N in the right direction.