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Solve for the indicated variable: 2[x + 3(x - 1)] = 18

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2(x+3(x-1))=18\\2(x+3x-3)=18 \\ 4x-3=18/2 \\ 4x-3=9 \\ 4x=9+3 \\ 4x=12 \\ x=12/4 \\ x=3
User Stefan Bollmann
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3 votes

2[x + 3(x - 1)] = 18\\ x+3x-3=9\\ 4x=12\\ x=3
User Seal Blue
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