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If (mx + 7)(5x +n)=px^2+15x+14, what is m(n+p)? A) -10 B) -520 C) 480 D) 2 E) 520
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If (mx + 7)(5x +n)=px^2+15x+14, what is m(n+p)? A) -10 B) -520 C) 480 D) 2 E) 520
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Jul 13, 2018
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If (mx + 7)(5x +n)=px^2+15x+14, what is m(n+p)?
A) -10
B) -520
C) 480
D) 2
E) 520
Mathematics
high-school
Isa Souza
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Isa Souza
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The answer you are looking for is C
Sergiy Medvynskyy
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Jul 16, 2018
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Sergiy Medvynskyy
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(mx + 7)(5x + n) = 5mx^2 + mnx + 35x + 7n
= 5mx^2 + (35 + mn)x + 7n
= px^2 + 15x + 14
7n = 14
n = 2
35+mn = 15
35+ m(2) = 15
35+ 2m = 15
2m = 15-35
2m = -20
m = -10
p = 5m
= 5(-10)
=-50
m(n + p) = -10(2 -50)
= 480
Mark Dowell
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Jul 20, 2018
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Mark Dowell
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