Question

20 PTS!!!David's company reimburses his expenses on food, lodging, and conveyance during business trips. The company pays $60 a day for food and lodging and $0.65 for each mile traveled. David drove 600 miles and was reimbursed $3,390. Part A: Create an equation that will determine the number of days on the trip. (3 points) Part B: Solve this equation justifying each step with an algebraic property of equality. (6 points) Part C: How many days did David spend on this trip? (1 point)

Answer 1

Part A)

$60 for each day of the trip (d) + $0.65 * the number of miles (600 mi) = the total cost ($3390):


`60d + 390 = 3390`

Part B)


`60d + 390 = 3390` (Given equation)

`60d + 390 - 390 = 3390 - 390` (Subtraction property of Inequalities)

`60d = 3000` (Simplification)

`(60d)/(60) = (3000)/(60)` (Division property of inequalities)

`d = 50` (Simplification)

Part C)

David spent 50 days on his trip.

Answer 2

The company pays $60 a day for food and lodging and $0.65 for each mile traveled.

David drove 600 miles and was reimbursed $3,390.

Part A:

Let the number of days of trip be = x

Equation forms:

`600(0.65)+60x=3390`

=>
`390+60x=3390` .......(1)

Part B:

Solving (1) for x.

`390+60x=3390` (given)

Applying subtraction property of equality;

`60x+390-390=3390-390`

Now simplifying this we get;

`60x=3000`

Applying division property by dividing 60 on both sides, we get

x = 50

Part C:

We get x = 50, so David spent 50 days on the trip.