Question

What is the hydroxide concentration of a solution with a pH of 12.80?

Answer 1

Step1 : To convert from pH to ion concentrations,first apply equation 17-1 to calculate [H3O+]. Then make use of water equilibrium to calculate [OH-]
Step 2 : We must rearrange equation pH = -log [H+] , in order to solve for concentration
Step 3 : log [H+] = -pH and [H+] = 10 -pH
Step 4 ; Now substitute and evaluate:
[H+] = 10-3.05 = 8.9 x 10-4 M
Step 5: To determine the hydroxide ion concentration,we need to rearrange the water equilibrium expression:
Kw = 1.0 x 10 -14 = [H3O+]eq [OH-] and [OH-]eq = 1.0 x 10- 14 / [H3O+]
now susbtitute and evaluate:
= 1.0 x 10- 14 / 8.9 x 10-4 = 1.1 x 10-11 M

Sample protblem 2 : What is the OH- ion concetraion of a solution of NaOH with pH 13.40 ?
Solution:
Step 1 : First find pOH from the given pH:
pH + pOH = 14
pOH = 14 - 13.40 = 0.60
Step 2 : As you have now the value of pOH you can find the OH- ion concentration using formula
pOH = -log [OH-]
[OH- ] = 10 - pOH = 10 - 0.60 = 0.25 M

Answer 2

6.31 × 10^-2M

Step-by-step explanation:

pH +pOH=14

14-12.80=1.20

10^-1.2=.0631

move the decimal two places to the right

=6.31 × 10^-2