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Which is the general form of the equation of the circle shown? x2 + y2 + 4x – 2y – 4 = 0 x2 + y2 + 4x – 2y + 2 = 0 x2 + y² – 4x + 2y – 4 = 0 x2 + y² – 4x + 2y + 2 = 0

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Answer:

THE ANSWER IS A

Explanation:

User Guiwhatsthat
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For the first picture, the center is (-2,1) and the radius is 3.
For the second picture, the center is (-2,1) and the radius is square root of 3.
For the third picture, the center is (2,-1) and the radius is 3.
For the last picture, the center is (2,-1) and the radius is square root of 3.
Which is the general form of the equation of the circle shown? x2 + y2 + 4x – 2y – 4 = 0 x-example-1
Which is the general form of the equation of the circle shown? x2 + y2 + 4x – 2y – 4 = 0 x-example-2
Which is the general form of the equation of the circle shown? x2 + y2 + 4x – 2y – 4 = 0 x-example-3
Which is the general form of the equation of the circle shown? x2 + y2 + 4x – 2y – 4 = 0 x-example-4
User DINESH Adhikari
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