Question

Which is the next logical step in balancing the given equation?

CS2(l) + Cl2(g) CCl4(l) + S2Cl2(l)
A.) Place the coefficient 2 in front of sulfur dichloride (S2Cl2).
B.)Place the coefficient 3 in front of the chlorine molecule.
C.)Leave the equation alone as it is already balanced.
D.) Place the coefficient 4 in front of carbon disulfide(CS2).
E.)Place the coefficient 2 in front of carbon tetrachloride(CCl4).

Answer 1

CS2(l) +Cl2(g)→CCl4(l) + S2Cl2 (l)

The next logical step in balancing the equation above is place the coefficient 3 in front of the chlorine molecule ( answer B)

Step-by-step explanation

When coefficient 3 in placed in front of chlorine molecule the balanced equation is as below

• CS2 (l) +3Cl2 (g) → CCl4 (l) + S2Cl2 (l)

• According to the law of mass conservation the number of atom in side of reactant should be equal to the side of product.

• The reaction above is balanced because the number of atom is equal in both side.

• For example there are 2 atoms of S in side of product and 2 atoms of S in the product side.s

Answer 2

B. For balancing this equation: it originally starts with one carbon and two sulfurs and on the reactant side, you still end up with one carbon and two sulfurs. As for chlorine, to balance the equation you will need 6 chlorine molecules, and since chlorine is a diatomic molecule on the left it is Cl2. Therefore, to get 6 molecules of chlorine you will need 3 Cl2.