Calculate the amount of heat (in kilojoules) required to vaporize 2.97 kg of water at its boiling point. (δhvap

asked Jun 19, 2018 194k views

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$Given:\\m=2.97kg\\c_p=2,257 (kJ)/(kg) \\\\Find:\\Q=?\\\\Solution:\\\\Q=c_pm\\\\Q=2,257 (kJ)/(kg)\cdot2.97kg= 6703,29kJ$

Schellsan answered Jun 26, 2018

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