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If two sides of a triangle are 12 and 17, and the included angle is 60, what is the area of the triangle

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The area of a triangle is half the product of two sides times the sine of the included angle.


A= (1)/(2)*12*17*sin(60^o) =102* ( √(3) )/(2)=51 √(3) \approx 88.33 \ units^2
User Yasiru G
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