We are given the function
f(x) = 2(1/2)^1
Firstly, let f(x) = y
Then, y = 2(1/2)^x
To find y, substitute the value of x into the function.
y = 2(1/2)^x
Find y, when x = -1
y = 2(1/2)^-1
y = 2 ( 1/ 1/2)
y = 2(2 x 1 / 1)
y = 2 x 2
y= 4
When x = -1 , y = 4
find y, when x = 0
y = 2(1/2)^0
In mathematics, anything raise to the power of zero is 1
Therefore, (1/2)^0 = 1
y = 2 x 1
y = 2
When x = 0 , y = 2
find y, when x = 1
y = 2(1/2)^1
y = 2 * 1/2
y = 2/2
y = 1
when x = 1, y= 1
find y, when x = 2
y = 2(1/2)^2
(1/2)^2 = (1/4)
y = 2(1/4)
y = 2x 1/4
y = 2/4
y = 1/2 or 0.5
When x = 2, y= 1/2 or 0.5
The new table becomes
x y
-1 4
0 2
1 1
2 1/2