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An aqueous solution contains 0.050 m of methylamine, with kb = 4.4 x 10-4. what is the percent ionization and the ph of the solution?

User Krummens
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The base dissociation constant or Kb is a value used to measure the strength of a specific base in solution. To determine the percent ionization of the substance we make use of the Kb given. Methylamine or CH3NH2 when in solution would form ions:

CH3NH2 + H2O < = > CH3NH3+ + OH-

Kb is expressed as follows:


Kb = [OH-] [
CH3NH3+] / [CH3NH2]

Where the terms represents the concentrations of the acid and the ions.

By the ICE table, we can calculate the equilibrium concentrations,
CH3NH2 CH3NH3+ OH-
I 0.05 0 0
C -x +x +x
--------------------------------------------------
E 0.05-x x x

Kb = [OH-] [CH3NH3+] / [CH3NH2] = 4.4 x 10^-4

4.4 x 10-4 = x^2 / 0.05-x

Solving for x,

x = [OH-] = 0.00448 M

percent ionization = 0.00448 / 0.05 x 100 = 8.96%

pH = 14 + log 0.00448 = 11.65

User Veno
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