that is confusing but I will try to make sense of it

is what I think you aer getting
it is undefined in values of x where you divide by 0
set denomenator to 0 and solve
0=(x-3)(x+2)(x-5)
0=x-3
3=x
0=x+2
-2=x
0=x-5
5=x
undefined at x=-2, x=3 and x=5
bobby is correct because of math and it is undefined when you divide by 0