Question

Find the acceleration of a toy place whose velocity as a function of time is given by the graph belowat a) t = 4.00 s b) t = 9.00 s and c) t = 11.0 s.

Answer 1

a) 1 m/s^2

b) -4 m/s^2

c) 0 m/s^2

Explanation:

The acceleration is given by the following equation:

`a=(\Delta v)/(\Delta t)=(v_f-v_i)/(t_f-t_i)`

Therefore:

a) t = 4 s

`a=(3-(-3))/(6)=(3+3)/(6)=(6)/(6)=1`

b) t = 9 s

`a=(-5-3)/(10-8)=(-8)/(2)=-4`

c) t = 11 s

`a=(-5-(-5))/(12-10)=(-5+5)/(2)=(0)/(2)=0`