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Helppppplpppppppp pleaseeee

Helppppplpppppppp pleaseeee-example-1
User Siena
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In the general form, the standard form looks like this:
Ax + By = C

First, get the equation of the line in a slope-intercept form then change it into a standard form equation.

The slope-intercept form looks like this in general form:
y = mx + b

Find two points on the plain and use the slope formula. In the picture above, they have already marked two points on the line.


(2 - (-1))/(3 - (-3)) \\ \\ (3)/(6) \\ \\ (1)/(2)

Now get the y-intercept form. By looking at the graph, the line intercepts at the point (0, 1/2).

Plug these into the slope-intercept form.

y = (1/2)x + (1/2)

Convert the slope-intercept form into a standard form.

y = (1/2)x + (1/2)
2y = x + 1 <-- Multiplied each side by 2
2y - x = 1 <-- Subtracted each side by x

The third option is the correct answer because 2y - x = 1 can be rearranged to become -x + 2y = 1.
User Lorin
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