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Factor completely n^4-1
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Factor completely n^4-1

User TLS
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2 Answers

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Answer:(n + 1)(n - 1)(n^2 + 1)

User Sergey Karavaev
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8.1k points
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n^4 - 1 = (n^2 - 1)(n^2 + 1)

= (n + 1)(n - 1)(n^2 + 1)
User Qtxo
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