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Factor completely n^4-1
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Factor completely n^4-1
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Mar 10, 2018
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Factor completely n^4-1
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Answer:(n + 1)(n - 1)(n^2 + 1)
Sergey Karavaev
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Mar 12, 2018
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Sergey Karavaev
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n^4 - 1 = (n^2 - 1)(n^2 + 1)
= (n + 1)(n - 1)(n^2 + 1)
Qtxo
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Mar 16, 2018
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