Question

What is the probability of drawing two yellow marbles if the first one is NOT placed back into the bag before the second draw? Their is 10 marbles total, 2 yellow, 3 pink, and 5 blue

Answer 1

`(4)/(45)`

Explanation:

We are given that

Total number of marbles=10

Number of yellow marble=2

Number of pink marble=3

Number of blue marble=5

We have to find the probability of drawing two yellow marbles if the first one is not placed into the bag before the second draw.

Probability: P(E)=
`(Number\;of\;favorable\;cases)/(total\;number\;of\;cases)`

The probability of drawing first yellow marble=
`(2)/(10)`

The probability of drawing first yellow marble=
`(1)/(5)`

When first yellow marble is not placed back into the bag before the second draw.

Then,number of remaining yellow marble=1

Total number of marbles=9

The probability of drawing second yellow marble =
`(4)/(9)`

Now, the probability of drawing two yellow marbles =
`(1)/(5)* (4)/(9)=(4)/(45)`

Hence, the probability of drawing two yellow marbles=
`(4)/(45)`